1、搬運物總重量:W=600KG Total weight of load:W=600KG 2、搬送速度:V=9.5m/min Conveyance speed:V=9.5m/min 3、與道軌之摩擦系列:μ=0.15 And the friction series track: =0.15 4、鏈輪轉(zhuǎn)動效率:η1=0.95 Sprocket transmission efficiency:η1=0.95 5、減速機轉(zhuǎn)動效率:η2=0.9 Reducer transmission efficiency:η2=0.9 6、運轉(zhuǎn)時間:8小時/日 Operation time:8 hours/day 7、啟動次數(shù):1回/分,中沖擊 Times of starting:1 time/min,impact 8、使用電源:三相220V,60Hz Power applied:three-phase 220v,60Hz |
|
減速比 REDUCTION RATIO |
選型注意事項 | 計算范例 | |||||
由必要的入力軸回轉(zhuǎn)數(shù)及出力軸回轉(zhuǎn)數(shù)來選定減速比 Reduction ratio sbould be decided by input shaft revolutions and outpu shaft revolutions necessary 1、先求出輸送帶滾輪回轉(zhuǎn)數(shù)(N1) Find conveyor wheel revohutions(N1) diameter*π) 2、再求出減速機出力軸回轉(zhuǎn)數(shù)(N2) Find reducer output shaft revolutions(N2) N2=N1×鏈輪齒數(shù)減速比 N2=N1*sprovket wheel reduction ratio 3、以三相60Hz的馬達計算減速比(τ) Calculate reduction ratio of three-phase motor with frequency of 60Hz T=出力軸回轉(zhuǎn)數(shù)/入力軸回轉(zhuǎn)數(shù)(馬達轉(zhuǎn)數(shù)N) T=output shaft revolutions/input shaft revolutions(motor' s rpm N) |
1、N1=V/(D ) =9.5/(0.2 3 14)15r/min(RPM) 2、N2=N1×(26/13) =15×π × . ×2/1=30r/min(RPM) 3、N2/N=30/1800=1/60(馬達轉(zhuǎn)速) |
||||||
扭力 TORQUE |
選型注意事項 | 計算范例 | |||||
決定減速比后,由使用機械之條件換算其扭力 After reduction ratio is decided,the correspoding torque can be found according to its mechanical conditions 1、先算出輸送帶滾輪之扭力(T1)T1=(μ×荷重 )/η1 firstly find torque(T1)of conveyance wheel ratio T1=(m*load*wheel radios)/η1 2、再換算成減速機出力軸所須扭力(T2) then convert the torque(T1)to the torque(T2)necessary for the output shaft of reducer
T2=(T1×鏈輪減速比)/η2"
T2=(T1*sprocket reduction ratio)/η2" |
1、T1=μ×W(D/2)/ 2、T1=(T1× )/ η1 =0.15×600×(0.2/2)/0.95=9.5kgf-m η2 =(9.5×1/2)/0.9=5.28kgf-m |
||||||
負荷條件 LOAD CONDMONS |
選型注意事項 | 計算范例 | |||||
原動機 Prime mover |
傳動機負荷等級 Driven machine Load Classifieation |
每日使用時間 Duration of Service per day |
T3=T2×K =5.28×1.26=6.6kgf-m |
||||
0.50hr | 2hrs | 8-10hr | 10-24hr | ||||
電動機 Electric Motor |
均一負荷 Uniform | 0.8 | 0.9 | 1 | 1.25 | ||
中沖擊 Medium Shock | 0.9 | 1 | 1.25 | 1.5 | |||
重沖擊 Heavy Shock | 1 | 1.25 | 1.5 | 1.75 | |||
補正扭力=減速機出力軸扭力×系數(shù) Corrective torque = reducer shaft torque × conefficient |
|||||||
馬力 Hores power |
選型注意事項 | 計算范例 | |||||
1、最后換算成馬力(Hp)Hp=(補正扭力 )/716.3 |
Hp=(T3 )/716.2=(6.6 )/716.2=0.3 1/2Hp馬達適用(For 1/2Hp motor) |
鏈輪 SPROCKET | 1 | ||||||
齒輪 CEAR | 1.25 | ||||||
三角皮帶 BELT | 1.5 | ||||||
平皮帶 FLATBELT | 2.5 |
東莞市凱東電機有限公司聯(lián)系方式
全國統(tǒng)一服務熱線:400-616-0306
備案:粵ICP備13073035號
電話:0769-85845809 傳真:0769-85098131
地址:東莞市大嶺山石大路293號3棟
版權所有: 版權所有:東莞市凱東電機有限公司 Copyright Reserved技術支持:天度營銷網(wǎng)站